Sanders Overtakes Clinton in Wisconsin: Poll
The latest Wisconsin poll by Marquette Law School has placed Bernie Sanders ahead of Hillary Clinton.
The poll was nearly a tie, seeing Sanders win with 44 percent of the vote to Clinton’s 43 percent.
The Hill reports:
The Vermont senator trailed Clinton by a 9-point margin in Wisconsin, 50–41 percent, in November.
The poll also finds Sanders matching up better than Clinton against top Republicans in hypothetical general election races in the Badger State.
Sanders defeats GOP primary front-runner Donald Trump by 20 points, 54–34 percent, while Clinton only wins by 10 points, 47–37 percent.
He also defeats Ted Cruz by an 18-point margin, 53–35, while Clinton ties the Texas senator, 43–43.
And Sanders trumps Marco Rubio by an identical margin, 53–35, while Clinton narrowly edges Rubio by a 44–43 margin.
Charles Franklin, the director of the Marquette poll, said Sanders is especially strong in head-to-head matchups because he draws support from independents in the state.
The poll surveyed 343 Democratic primary voters from Feb. 18–21 and has a 6.9 percent margin of error.
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